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3 years ago

WILL GIVE BRANLIEST PLEASE HELP!

Mathematics

1 answer:

dimulka [17.4K]3 years ago

6 0

The equation x+3=9 is true if and only if x=6.

A bioconditional statement is always written in the “if and only if” form

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Can someone determine the answer to -3+-5 and explain the steps using a number line

UNO [17]

I hope you understood....if not...comment and I will be willing to still help

8 0

3 years ago

Read 2 more answers

I need to find the value of x and the value

enot [183]

Answer:

Step-by-step explanation:

Divide 24 by 6 which will give you 4

5 0

3 years ago

Help pls , will give brainliest!

m_a_m_a [10]

<h3>Answer: 6</h3>

=======================================

Work Shown:

1 liter = 1000 mL

3 liters = 3000 mL

I multiplied both sides by 3.

Divide that result over 500 to get 3000/500 = 6

So she'll need to buy 6 cartons.

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You could also solve like this:

(1 carton)/(500 mL) = (x cartons)/(3000 mL)

1/500 = x/3000

1*3000 = 500*x ... cross multiply

3000 = 500x

500x = 3000

x = 3000/500 .... dividing both sides by 500

x = 6

6 0

3 years ago

Find the solution to this system of equations <br> 3x+2y+3z=3 4x-5y+7z=1 2x+3y-2z=6 <br> x=? Y=? Z=?

Ede4ka [16]

Answer:

The solution is $x=2,\ y=0,\ z=-1.$

Step-by-step explanation:

You are given the system of three equations:

$\left\{\begin{array}{l}3x+2y+3z=3\\4x-5y+7z=1\\2x+3y-2z=6\end{array}\right.$

Multiply the first equation by 4, the second equation by 3 and subtract them. Then multiply the third equation by 2 and subtract it from the second equation:

$\left\{\begin{array}{l}3x+2y+3z=3\\4(3x+2y+3z)-3(4x-5y+7z)=4\cdot 3-3\cdot 1\\4x-5y+7z-2(2x+3y-2z)=1-2\cdot 6\end{array}\right.\Rightarrow \\\\\left\{\begin{array}{l}3x+2y+3z=3\\12x+8y+12z-12x+15y-21z=12-3\\4x-5y+7z-4x-6y+4z=1-12\end{array}\right.$

So,

$\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\-11y+11z=-11\end{array}\right.\Rightarrow \left\{\begin{array}{l}3x+2y+3z=3\\23y-9z=9\\y-z=1\end{array}\right.$

Multiply the third equation by 23 and subtract it from the second equation:

$\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23(y-z)=9-23\cdot 1\end{array}\right.\Rightarrow \left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23y+23z=9-23 \end{array}\right.$