Answer:
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 91 - 3.51 = 87.49
The upper end of the interval is the sample mean added to M. So it is 91 + 3.51 = 94.51
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.