To solve this problem we need to use the equations related to Elastic Potential Energy, which allows us to know the Energy stored in a spring based on its elastic constant and its respective compression. By definition it is described as
Where,
k = Spring constant
x = Displacement
Our values are given as
As we do not know the spring constant but if the energy stored at the compression given then,
In the case of the second compression and understanding that the spring constant is intrinsic to the internal force of the spring, then
Replacing,
Therefore the elastic potential energy in the spring at this elongation is 45J
Condensation.
Would be the right answer.
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Answer:
The minimum speed when she leave the ground is 6.10 m/s.
Explanation:
Given that,
Horizontal velocity = 1.4 m/s
Height = 1.8 m
We need to calculate the minimum speed must she leave the ground
Using conservation of energy
Put the value into the formula
Hence, The minimum speed when she leave the ground is 6.10 m/s.
Answer:
Time taken to cover the distance 11.45 s.
Explanation:
The given parameters:
Initial Velocity(u)=24 m/s
Acceleration (a)=8
Distance or Displacement(s)=800 m
Displacement or Distance is equal in the above because it travels in a straight line.
We have to apply Second Equation of Motion,
s=ut+
800=24t + 4
200=6t +
+ 6t - 200=0
Solving, the quadratic equation to find out the roots, we get that the possible values of t will be 11.45 s and a negative value.
The negative value will be neglected as time cannot be negative.
Hence, the time taken is 11.45 s.