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3 years ago

What occurs to the arrangement of water molecules as water melts

2 answers:

7 0

The arrangements of the water molecules they begin to spread apart. As the water(ice) melts the molecules develop fewer compact and start juddering harder until the ice has changed state into liquid.

labwork [276]3 years ago

6 0

they become less orderly... is the answer for sure

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A radioactive particle has a half life of 1 second. If it moves at 3/5 the speed of light, from my point of view standing still

AVprozaik [17]

The half-life observed by an observer at rest is 1.25 s

Explanation:

In this problem, the particle is travelling at a significant fraction of the speed of light: therefore, we have to consider the phenomenon of the time dilation. The half-life of the particle as measured by an observer at rest is given by

$T=\frac{T_0}{\sqrt{1-(\frac{v}{c})^2}}$

where

$T_0$ is the proper half-life of the particle

v is the speed of the particle

c is the speed of light

For the particle in this problem,

$T_0 = 1 s$

$v=\frac{3}{5}c=0.6 c$

Substituting into the equation, we find:

$T=\frac{1}{\sqrt{1-(\frac{0.6c}{c})^2}}=1.25 s$

#LearnwithBrainly

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3 years ago

You eat an apple, so what energy transformations will it go through?

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The energy transform into the energy of ATP

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3 years ago

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A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. The d

-BARSIC- [3]

Answer:

a) $t=6.37s$

b) $t=3.3333s$

Explanation:

The knowable variables are the initial hight and initial velocity

$s_{o}=80ft$

$v_{os}=64ft/s$

The equation that describes the motion of the ball is:

$s=80+64t-16t^{2}$

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

$0=80+64t-12t^{2}$

a) Solving for t, we are going to have two answers

$t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

a=-16

b=64

c=80

$t=-1.045 s$ or $t=6.378s$

Since time can not be negative the answer is t=6.378s

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

$v_{y}=v_{o}+gt$

at maximum point the velocity is 0

$0=64-32.2t$

Solving for t

$t=1.9875 s$

Now, we must know how much distance does it take to reach maximum point

$s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft$

So, the ball pass the top of the building on its way down at 160 ft

$160=80+64t-16t^{2}$

Solving for t

$t=2s$ or $t=3.333s$

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

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3 years ago

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How do you find density of a regular solid?

Effectus [21]

Put the object or material on a scale to figure out its mass. 3. Divide the mass by the volume to figure out the density (p = m / v). You may also need to know how to calculate the volume of a solid so use the formula

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