Answer:
D.)it orbits near the Kepler belt
Explanation:
The Kuiper belt is an area similar to the asteroide belt extending from the orbit of Neptune to about 50 AU from the Sun. It mainly consists of icy asteroids and dwarf planets, which are rocky objects big enough to be defined as planet but that do not have enough gravity to clear their orbit from other obejcts.
Pluto was discovered in 1930 - initially it was classified as a planet, although it is much smaller than the other 8 planets of the Solar System. However, it has been recently de-classified to dwarf planet because its gravity is not enough to clear its orbit from other objects (asteroids). Pluto is located inside the Kuiper belt, so option D is correct. Other dwarf planets in the Kuiper belt are for instance Haumea and Makemake.
here's the solution,
The <em>radius</em> of the circle =<u> 3 km</u>
distance covered = <em>circumference</em> of the circle,
So, Circumference :
=》

=》

=》

(a). Distance covered by moving object is 18.84 km
(b). 0 km
now, Displacement of the object is 0 km, because displacement is the shortest distance from stating point to the destination, but the object returns back to the starting point, hence magnitude of displacement is 0.
Answer:
The scrum master can suggest that:
Postpone the work on system integration for a while until the train is in sustain and enhance the section of road map of implementation
Explanation:
System Demo:
It is such a software that is used to measure the progress of Agile Release Train.
As the teams didn't expect that the integration of system will be a difficult task and they ultimately failed to accomplish the goal of integration so that scrum master asked them to stop working on the system integration until the Agile Release Train's sustainability and to improve and optimize the implementation of road map.
Answer:
water is in the vapor state,
Explanation:
We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat
E = Q₁ + 
Where Q1 is the heat required to bring water from the current temperature to the boiling point
Q₁ = m
(
-T₀)
Q₁ = 50 4180 (100 - 37)
Q₁ = 1.317 10⁷ J
Let's calculate the energy so that all the water changes state
= m L
= 50 2,256 106
= 1,128 10⁸ J
Let's look for the energy needed to convert all the water into steam is
Qt = Q₁ +
Qt = 1.317 107 + 11.28 107
Qt = 12,597 10⁷ J
Let's calculate how much energy is left to heat the water vapor
ΔE = E - Qt
ΔE = 10¹⁰ - 12,597 10⁷
ΔE = 1000 107 - 12,597 107
ΔE = 987.4 10⁷ J
With this energy we heat the steam, clear the final temperature
Q = ΔE = m
(
-To)
(
-T₀) = ΔE / m 
= T₀ + ΔE / m 
= 100 + 987.4 10⁷ / (50 1970)
= 100 + 1,002 10⁵
= 1,003 10⁵ ° C
This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components
Answer:
The work done in stretching the spring is 0.875 J.
Explanation:
Given that,
Force = 140 N
Natural length = 60-40 = 20 cm
Stretch length of the spring = 65-60 = 5 cm
We need to calculate the spring constant
Using formula of Hooke's law




We need to calculate the work done


On integration



Hence, The work done in stretching the spring is 0.875 J.