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tatyana61 [14]
3 years ago
11

A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles

of butane. What is the total pressure of the mixture inside the flask?
Physics
1 answer:
Julli [10]3 years ago
7 0
Applying the general gas equation : PV=nRT
V = 1.50 litres
R = <span>0.08205746 L atm/K mol
T = </span><span>25°C = 25+273 = 298 K
n = </span>0.158 moles+0.09 moles+<span> 0.044 moles = 0.292 moles
</span><span>Re arranging the equation:
P = nRT / V = (0.158 + 0.09 + 0.044) mol x (0.08205746 L atm/K mol)
 x (25 + 273)K / (1.50 L)
= 4.76 atm
= 482 kPa
= 3617 mmHg</span>
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Let's replace

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The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

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