The weight of a person increase when the elevator is going up.
<h3>
Weight of the person in the elevator</h3>
The weight of the person in the elevator is calculated as follows;
<h3>When the person is going up</h3>
F = ma + mg
F = m(a + g)
where;
- a is acceleration of the person
- g is acceleration due to gravity
<h3>When the person is going down</h3>
F = mg - ma
F = m(g - a)
Thus, the weight of a person increase when the elevator is going up.
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A perfect black body can’t be realized
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Answer:
The ratio of the energy stored by spring #1 to that stored by spring #2 is 2:1
Explanation:
Let the weight that is hooked to two springs be w.
Spring#1:
Force constant= k
let x1 be the extension in spring#1
Therefore by balancing the forces, we get
Spring force= weight
⇒k·x1=w
⇒x1=w/k
Energy stored in a spring is given by
where k is the force constant and x is the extension in spring.
Therefore Energy stored in spring#1 is, 
⇒
⇒
Spring #2:
Force constant= 2k
let x2 be the extension in spring#2
Therefore by balancing the forces, we get
Spring force= weight
⇒2k·x2=w
⇒x2=w/2k
Therefore Energy stored in spring#2 is, 
⇒
⇒
∴The ratio of the energy stored by spring #1 to that stored by spring #2 is
2:1