Answer:
Hey there!
We have tangent 29=h/400
Thus, tangent 29 times 400=h
h=221.7 feet.
The height of the kite is 221.7 feet.
Hope this helps :)
To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)
so
A+ 10 = c -10 + 10
we get
A+ 10 = c
lets say it wasn't -10 but positive 10.
A = c + 10 then we would subtract 10 from both sides
A -10 = c + 10 - 10
we get
A - 10 = C
Answer:
3,-4
Step-by-step explanation:
im not sure if this is right or not but I tried
Answer:
-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C
Step-by-step explanation:
∫ 15 sin(√(at)) dt
Use substitution:
If x = √(at), then:
dx = ½ (at)^-½ (a dt)
dx = a / (2√(at)) dt
dx = a/(2x) dt
dt = (2/a) x dx
Plugging in:
∫ 15 sin x (2/a) x dx
30/a ∫ x sin x dx
Integrate by parts:
If u = x, then du = dx.
If dv = sin x dx, then v = -cos x.
∫ u dv = uv − ∫ v du
= 30/a (-x cos x − ∫ -cos x dx)
= 30/a (-x cos x + ∫ cos x dx)
= 30/a (-x cos x + sin x + C)
Substitute back:
30/a (-√(at) cos(√(at)) + sin(√(at)) + C)
-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C
Answer:
4 it would go back in order
Step-by-step explanation:
