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3 years ago

Caroline runs 3 1/2miles in 22 1/4 mins. how many miles does she run per mile

1 answer:

8 0

We have changed 3 1/2= 7/2 and 22 1/4= 89/4
and the speed of Caroline is = distance: time= 89/4:7/2= 89/4 x 2/7= 89/14= 6.36 miles per minute
notice you wrongly wrote per mile

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Help please will mark brainliest!!!

Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either, because it looked bigger than what a 30° angle would be.

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2 years ago

Brendan has 33 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 615 cents, how many

Amanda [17]

If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.

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2 years ago

If the first chapter of a certain book is 40 pages long and makes up 20% of the book, how many pages does the entire book have?

Setler [38]

Answer:

200

Step-by-step explanation:

20% of a book = 40 pages

100% of a book = x pages

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20x/20 = 4000/20 Do the division

x = 200 Answer

5 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$