2 years ago

How do I show my work for this problem?

1 answer:

7 0

Perhaps you can try plugging your value of x in and showing that x+25=40. That is probably what your teacher wants to see

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For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

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2 years ago

Mr Riley baked 1692 chocolate cookies. He sold them in boxes of 36 cookies each. How much money did he collect if he sold them a

Nimfa-mama [501]

I believe he would earn $376 dollars

1692÷36= 47 boxes

47 times 8 is 376 Dollars

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2 years ago

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Usimov [2.4K]

Over 3 up 6, or better know as 3/6

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2 years ago

4 and 2/5 - 2 and 4/5

Mademuasel [1]

Answer:1.6

Step-by-step explanation:Hope this helps

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Divide 9x^2-21x-20 by x-1

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$9 x^{3}-30 x^{2} +x+20
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