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3 years ago

Please help me come up with an equation.

Mathematics

2 answers:

zloy xaker [14]3 years ago

7 0

Answer: 15 + 2.50x = y

Tcecarenko [31]3 years ago

4 0

Answer:

$15 + $2.50x=y

Step-by-step explanation:

$15 plus the $2.50 times every ride you go on (x) equals the total amount (y)

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The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation

Savatey [412]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = $\mu = 69$

Standard deviation = $\sigma = 7$

Formula : $z=\frac{x-\mu}{\sigma}$

Now At x = 55

$z=\frac{55-69}{7}$

$z=-2$

At x = 76

$z=\frac{76-69}{7}$

$z=1$

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = $0.8185 \times 100 = 81.85\%$

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

8 0

4 years ago

A CD is circular and has a diameter of 6 centimeters. Which is closest to the area of the CD? Use 3.14 for π

prohojiy [21]

Answer:

28.26 cm²

Step-by-step explanation:

Area of a circle = πr²

r = diameter/2

r = 6/2 = 3

A = (3.14)(3)²

A = 28.26 cm²

5 0

3 years ago

Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit

Anestetic [448]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let $\hat p$ = the sample proportion of defectives.

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P( $\hat p$ > 0.13)

P( $\hat p$ > 0.13) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ > $\frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}} }$ ) = P(Z > -2.74) = P(Z < 2.74)