Okay so how you solve an equation is listed here:
hmm lets say 4x + 1 ÷2= 6
4x + 1 ~÷2~= 6
~x2~ x2
------------------------
4x~+1~ 12
~ -1~ -1
-------------------------
4x. 11
÷4. ÷4
-----------------------
x. = 2.75
The required boxplot isn't attached, an hypothetical solution is given which could be applied to solve your actual task.
Answer:
Kindly check explanation
Step-by-step explanation:
From the attached picture, the median and upper quartile value of the boxplot are :
The median of a dataset plotted on a box and whisker plot can be obtained directly from the plot as the point where a vertical line splits the box. The line inside the box gives the median of the data. The Q3 value which is the upper quartile is depicted on the box and whisker plot as the endpoint of the box. The endpoint of the box gives the upper quartile value for the dataset.
In the attached boxplot , the median = 29
The upper quartile = 38
Answer:
26
Step-by-step explanation:
I don't totally understand you question but if its 4 pages originally then she takes 2 pages every class, then
56-4= 52 (56 pages minus the 4 she already took).
52/2= 26 (52 pages divided by 2 pages per class)
Answer:
x=y
Step-by-step explanation:
Answer:

Step-by-step explanation:
we have

Distribute in both sides


Combine like terms in both sides

group terms that contain the same variable
Adds 9x both sides


Subtract 26 both sides


Divide by 4 both sides

