<h3>
Answer: Choice C</h3>
cos(a - b) = cos(a)cos(b) + sin(a)sin(b)
In this case, we'd have a = 180 and b = q, so,
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
cos(180 - q) = cos(180)cos(q) + sin(180)sin(q)
cos(180 - q) = -1*cos(q) + 0*sin(q)
cos(180 - q) = -cos(q) + 0
cos(180 - q) = -cos(q)
A. Always
These lines<span> are </span>perpendicular<span> since their slopes are negative reciprocals.</span>
Answer:
K=-2.5
Step-by-step explanation:
because the line is in the middle of 2 and 3 and is below which means that it is negative
3x^3+2x^2-32x+2 | x-3
-----------------
-3X^3+9x^2 3x^2 +11x+1
-------------------------
/ 11x^2-32x+2
-11x^2+33x
------------------
/ x+2
-x+3
-------
/ 5
⇒ (3 x^3+2X^2-32x+2) : (x-3)= 3x^2+11x+1 rest 5
