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3 years ago

Help me Find the area of

Mathematics

2 answers:

Serhud [2]3 years ago

7 0

This is how I'd do it. Divide the shape into 2 different shapes, both would have the same area formula A=lw. so shape 1(the top one) would be A1=41*51=_____
The area for the 2nd one (the bottom one) would be A=64*38=______
Then, you just add up the results ;)
Hope that helps :)

andriy [413]3 years ago

3 0

I believe the answer is 4,523. Correct me if im wrong

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Please help, question is above in picture

Serhud [2]

-3.5 * 2 = -7
-3.5 * 3n = 10.5n

So there is (-7 - 10.5n) -2.5n

Now combine like terms
10.5n - 2.5n = 8n

ANSWER = -7 + 8n

4 0

3 years ago

Plz help I'll give brainlest

jarptica [38.1K]

<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 $m^2$ </h3><h3>3.Area of the trapezoid = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is = 1200 square in</h3><h3>8.The area of the rhombus is =84 $cm^2$ </h3><h3>9.Area of the trapezoid = 240 square ft</h3>

Step-by-step explanation:

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

=16× 18 square units

= 288 square units

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

=(9×5) $m^2$

=45 $m^2$

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (12+5) \times 4$ square in.

= 34 square in.

Height = 2 ft and parallel sides are 2 ft and 6 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (2+6) \times 2$ square ft

= 8 square ft

Diagonals are 6 cm and 9 cm.

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 6\times 9$ square cm

= 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 12\times 18$ square in

= 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

= 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = $\frac {1}{2} \times 14 \times 12$ $cm^2$

=84 $cm^2$

9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

= $\frac{1}{2} \times (24+16) \times 12$ square ft

= 240 square ft

8 0

3 years ago

-4x < 16<br> How do I solve this inequality?

agasfer [191]

Answer:

x>-4

Step-by-step explanation:

Divide by negative 4 on both sides, and since its a negative, you have to flip the inequality sign, so it comes out to be x> -4

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2 years ago

I really need to know theese and rhe rest plsss

gayaneshka [121]

Answer:

10.45?

Step-by-step explanation:

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Write the equation y=-1/2x+3 in standard form. how do I do this?

Lapatulllka [165]

Standard form is ax + by = c. Begin our transformation by multiplying both sides by 2 to get rid of the fraction. Notice that ax + by = c does not allow for fractions. Doing that multiplication gives us 2y=-x + 3. Now move the x over by the y by addition. x + 2y = 3. And there you go!

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3 years ago

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