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3 years ago

A tree planted today has a height of 5 feet and grows one foot each month.

Mathematics

1 answer:

sammy [17]3 years ago

3 0

Answer:

Liner function

x = 5 + n

Step-by-step explanation:

Given:

Height of tree = 5 ft

Grow per month = 1 ft

Find:

Equation:

Computation:

Assume;

New height of tree x

Number of month = n

x = 5 + 1(n)

x = 5 + n

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What is the radius of a sphere with a volume of 7961 cm", to the nearest tenth of a<br> centimeter?

statuscvo [17]

Answer:

12.4 cm

Step-by-step explanation:

Use the sphere volume formula, V = $\frac{4}{3}$ $\pi$ r³

Plug in the volume and solve for r, the radius:

V = $\frac{4}{3}$ $\pi$ r³

7961 = $\frac{4}{3}$ $\pi$ r³

1900.55 = r³

12.39 = r

So, the radius of the sphere is approximately 12.4 cm

6 0

3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

6 0

2 years ago

What i thissss pls help

zubka84 [21]

Answer: A

Step-by-step explanation:

5 is in the ones place rather that the tens place.

8 0

2 years ago

Read 2 more answers

How many solutions does a triangle with side lengths a = 4, A = 112º and b =<br>9 have?

Ainat [17]

Answer:

This case has NO solutions.

Step-by-step explanation:

Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.

This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

$\frac{sin(A)}{a} =\frac{sin(B)}{b}\\sin(B)=\frac{b\,sin(A)}{a}\\sin(B)=\frac{9\,sin(112^o)}{4}\\\\sin(B)=2.086$

As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).

Therefore, there is no angle we can find to build a triangle with the given data.

7 0

3 years ago

In this triangle, side AT = 24. Please give the value for the sine, cosine, and tangent for this diagram (Which is the marked an

sashaice [31]

The value of the sine, cosine and tangent of the figure will be found as follows:
a] Sine
sin x=(opposite)/(hypotenuse)
opposite=7
hypotenuse=25
thus:
sin x= 7/25

b] Cosine
cos x=adjacent/hypotensue
adjacent=24
hypotenuse=25
cos x=24/25

Tangent
Tan x=opposite/adajcent
opposite=7
adjacent=24
thus
tan x=7/24

5 0

3 years ago