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HACTEHA [7]
4 years ago
7

What is a natural number?

Mathematics
2 answers:
Fed [463]4 years ago
7 0
1 and 0 ..........................................................
WITCHER [35]4 years ago
5 0
MAYBE 1 AND 0 ISA NATURAL NUMBER
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I don’t know if the first one is right but could someone guess true or false?
victus00 [196]

Answer:

B) false D) true E) true

Step-by-step explanation:

Plug in numbers to disprove the first one.

Area formula for triangles says D is true

It's the Pythagorean's Theorem for Heaven's sakes.

3 0
4 years ago
Find the roots of the equation: y=4(X+4)^2 -12
Dafna1 [17]
0=4(x²+8x+16)-12
0=4x²+32x+64-12
0=4x²+32x+52
0=x²+8x+13
D=b²-4ac
D=64-52=12
x=(-b-√D)/2a
x=(-b+√D)/2a
x=(-8-2√3)/2= (-2(4+√3))/2= -(4+√3)
AND
x=(-8+2√3)/2=-2(4-√3)/2= -(4-√3)
3 0
4 years ago
The top of a house is 32 feet above ground. The basement floor is 12 feet below
lys-0071 [83]

12 feet below would be -12. from -12 to 0 would be 12 feet.

from 0 to 32 above would be 32 feet.

Total distance = 12 + 32 = 44 feet.

7 0
4 years ago
F(x)=(x-6)e^-3x find the interval in which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema
Over [174]
\bf f(x)=(x-6)e^{-3x}\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)]
\\\\\\
\cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}

set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there

there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema
5 0
3 years ago
Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.
hichkok12 [17]

Answer:

(x-3)^2+ (y+5)^2=10

Step-by-step explanation:

Given the equation of the circle: x^2 + y^2 - 6x + 10y + 24 = 0

We wish to express it in a Standard form:

We begin by re-arranging:

x^2 - 6x + y^2  + 10y  = - 24

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

x^2 - 6x +(-3)^2+ y^2  + 10y+5^2  = - 24+(-3)^2+5^2

Next, we factorize

(x-3)^2+ (y+5)^2  = - 24+9+25\\(x-3)^2+ (y+5)^2=10

This is the standard form.

6 0
3 years ago
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