select the equation of the line that passes through the point (3,-1) and is parallel to the line on the graph
1 answer:
ANSWER
y=-1
EXPLANATION
The given line in the graph has equation
This line is a horizontal line.
All horizontal line has a slope of 0.
Let the equation of the line that is parallel to this line be
The slope of this line must also be zero.
We substitute the slope, m=0 and the point (3,-1) into this equation to get:
Hence the required equation is
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Answer:
The standard form of the equation for this line can be:
l: 2x + 5y = -15.
Step-by-step explanation:
Start by finding the slope of this line.
For a line that goes through the two points and
,
.
For this line,
.
Find the slope-point form of this line's equation using
, and
- The point
(using the point
should also work.)
The slope-point form of the equation of a line
- with slope
and
- point
should be .
For this line,
, and
, and
.
The equation in slope-point form will be
.
The standard form of the equation of a line in a cartesian plane is
where
,
, and
are integers.
.
Multiply both sides of the slope-point form equation of this line by :
.
Add to both sides of the equation:
.
Therefore, the equation of this line in standard form is .