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3 years ago

I am having trouble 2(10-13x)=-34x+60

Mathematics

1 answer:

Elis [28]3 years ago

5 0

<span>x = 5 i beliavie :)..............................</span>

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Given csc x/ cot x= √2, find a numerical value of one trigonometric function of x.

hodyreva [135]

Answer:

Step-by-step explanation:

Note that

$\csc x=\dfrac{1}{\sin x}$

and

$\cot x=\dfrac{\cos x}{\sin x}.$

Then

$\dfrac{\csc x}{\cot x}=\dfrac{\frac{1}{\sin x}}{\frac{\cos x}{\sin x}}=\dfrac{1}{\cos x}=\sec x.$

Since $\dfrac{\csc x}{\cot x}=\sqrt{2},$ you have that $\sec x=\sqrt{2}.$

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3 years ago

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Write the equation of the line with x-intercept 3 and passing through the point (5.4)

kykrilka [37]

Answer: y=(1/5)m+3

Step-by-step explanation:

Start with the standard form of an equation of a straight line: y=mx+b, whre m is the slope and b the y-intercept (the value of y when x=0).

y=mx+b

We know b (3), so:

y=mx + 3

To find the slope, m, we can use the one given point, (5,4):

y=mx + 3 for (5,4) would be:

4 = m*5+3

1 = 5m

m = (1/5)

y=(1/5)m+3

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3 years ago

What is the perimeter of a square with side length 2x-3

NeTakaya

Perimeter of a square: side length * 4, since squares have equal side lengths

Take 2x - 3 for the side length and plug it into the formula.

(2x - 3) * 4 can be rewritten as 4(2x - 3)

Distribute 4 inside the parentheses.

8x - 12 = perimeter of the square

5 0

3 years ago

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Pierre stands on level ground at the point P, 5 metres from O.

GenaCL600 [577]

So hmm notice the picture below

thus $\bf \cfrac{4.24}{x}=\cfrac{2x+5}{2x}\implies 8.48x=2x^2+5x\implies 8.48x-5x=2x^2
\\\\\\
3.48x=2x^2\implies 0=2x^2-3.48x\implies 0=x(2x-3.48)
\\\\\\

\begin{cases}
0=x\\
----------\\
0=2x-3.48\\
3.48=2x\\\\
\cfrac{3.48}{2}=x\\\\
1.74=x
\end{cases}$

so, is clearly not 0, so it has to be 1.74

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3 years ago

P + 0.20p as an equivalent expression

andreev551 [17]

Answer:

An equivalent expression to p - 0.20p is 0.8p Hope this helps :)

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3 years ago