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pshichka [43]
3 years ago
9

Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minu

te. Plan B involves a fixed charge of $15 per month and call charges at $0.08 per minute. Which statement correctly compares the two plans?
Mathematics
1 answer:
Kay [80]3 years ago
4 0
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minute. Plan B involves a fixed charge of $15 per month and call charges at $0.08 per minute.

Plan A $10 + .10/minute

Plan B $15 + .08/minute

If 250 minutes are used:

Plan A: $10+$25=$35
Plan B: $15+$20=$35

If 400 minutes are used:

Plan A: $10+$40=$50
Plan B: $15+$32=$47

B is the correct answer. How to test it:

Plan A: $10+(.10*249 minutes)
$10+$24.9=$34.9

Plan B: $15+(.08*249 minutes)
$15+$19.92=$34.92

Plan A < Plan B if less than 250 minutes are used.
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Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,
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Answer:

The percentage change is 140%

Step-by-step explanation:

Given

L= 3W_1 ---- initial dimension

W_2 = 6m --- new width

A_2 = 45m^2 --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

Area =Length * Width

A_2=L * W_2

Make L the subject

L = \frac{A_2}{ W_2}

Substitute values for A and W

L = \frac{45m^2}{6m}

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L = 7.5m --- this is the length of the garden

Calculate the initial width:

L= 3W_1

Make W1 the subject

W_1 = \frac{1}{3} * L

W_1 = \frac{1}{3} * 7.5

W_1 = 2.5

So, the initial area is:

A_1 = L_1 * W_1

A_1 = 2.5 * 7.5

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The percentage change in area is:

\%A = \frac{A_2 - A_1}{A_1}

\%A = \frac{45 - 18.75}{18.75}

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\%A = 1.4

Express as percentage

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