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mel-nik [20]
3 years ago
5

A circle with circumference 6 has an arc with a 60° central angle.

Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

length of an arc = 1unit

Step-by-step explanation:

given that the circumference of a circle = 6

central angle = 60

length of the arc =?

recall that the circumference of a circle = 2πr

6 = 2πr

r = 6/2π

now to calculate the length of an arc

recall,

length of an arc = 2πr(Ф/360)

length of an arc = 2π(6/2π) × 60/360

length of an arc = 6 × 60/360

length of an arc = 360/360

length of an arc = 1unit

therefore the length of the arc whose circumference is 6 and arc angle is 60° is evaluated to be 1unit

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A Graduated Cylinder
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Ticket costs £63 plus a booking fee of 3%. <br> What is the total price of the ticket ?
Arte-miy333 [17]
The answer is £64.89.

Step by Step:

Take the original price multiplied by 0.03 ( the percent of a booking fee ) and add those amounts together.

Equation: 63 + 1.89 = 64.89
5 0
3 years ago
Given m&lt;12= 121 and m&lt;6= 75, find the measure of each missing angle.
slava [35]

Answer/Step-by-step explanation:

Given:

m<12 = 121°

m<6 = 75°

a. m<1 = m<6 (vertical angles)

m<1 = 75° (substitution)

b. m<12 = m<1 + m2 (alternate exterior angles)

121° = 75° + m<2 (substitution)

121° - 75° = m<2 (subtraction property of equality)

46° = m<2

m<2 = 46°

c. m<1 + m<2 + m<3 = 180° (angles on a straight line)

75° + 46° + m<3 = 180° (substitution)

121° + m<3 = 180°

m<3 = 180° - 121° (subtraction property of equality)

m<3 = 59°

d. m<4 = m<3 (vertical angles)

m<4 = 59° (substitution)

e. m<5 + m<4 + m<6 = 180° (angles on a straight line)

m<5 + 59° + 75° = 180° (substitution)

m<5 + 134° = 180°

m<5 = 180° - 134° (Subtraction property of equality)

m<5 = 46°

f. m<7 = m<12 (vertical angles)

m<7 = 121° (substitution)

g. m<8 = m<4 (vertical angles)

m<8 = 59° (substitution)

h. m<9 = m<6 (Alternate Interior Angles)

m<9 = 75° (substitution)

i. m<10 + m<9 = 180° (Linear Pair)

m<10 + 75° = 180° (substitution)

m<10 = 180° - 75° (Subtraction property of equality)

m<10 = 105°

j. m<11 = m<8 (vertical angles)

m<11 = 59° (substitution)

k. m<13 = m<10 (vertical angles)

m<13 = 105° (substitution)

l. m<14 = m<9 (vertical angles)

m<14 = 75° (substitution)

5 0
3 years ago
I NEED HELP PLEASE!!<br> PLEASE IM BEGGING YOU!!
Gennadij [26K]
A.) r=C/2(pi)
b.) 6.0
7 0
3 years ago
Given the formula:<br><img src="https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%20%2B%20a%7D%7B1%20-%20a%7D%20" id="TexFormula1
shtirl [24]

12 = \frac{1+a}{1-a} => 12(1-a)= 1+ a \\=> 12 -12a = 1 + a => 12a+1 = 12-1 \\=> 13a = 11 => a= \frac{11}{13}

ok done. Thank to me :>

8 0
2 years ago
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