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Anuta_ua [19.1K]
3 years ago
5

How many different arrangements of 7 letters can be formed if the first letter must be W or K (repeats of letters are allowed)?

Mathematics
1 answer:
mestny [16]3 years ago
4 0

Answer:

Written

tin

ten

tent

wit

Step-by-step explanation:

is this Correct

coz I don't get the queen

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Can someone answer this please?
koban [17]

Step-by-step explanation:

BDC = BAC

BAC =<u> 29°</u>

BOC = 2BDC

= 2×29

= <u>58°</u>

5 0
3 years ago
Read 2 more answers
A rectangle is constructed with its base on the​ x-axis and two of its vertices on the parabola yequals25minusxsquared. What are
Karolina [17]

Answer:

The answer is "\bold{\frac{32}{3}}\\"

Step-by-step explanation:

The rectangle should also be symmetrical to it because of the symmetry to the y-axis  The pole of the y-axis.  Its lower two vertices are (-x,0). it means that  

and (-x,0), and (x,0). Therefore the base measurement of the rectangle is 2x. The top vertices on the parabola are as follows:  

The calculation of the height of the rectangle also is clearly 16-x^2, (-x,16,-x^2) and (x,16,-x^2).  

The area of the rectangle:

A(x)=(2x)(16-x^2)\\\\A(x)=32x-2x^3

The local extremes of this function are where the first derivative is 0:

A'(x)=32-6x^2\\\\32-6x^2=0\\\\x= \pm\sqrt{\frac{32}{6}}\\\\x= \pm\frac{4\sqrt{3}}{3}\\\\

Simply ignore the negative root because we need a positive length calculation

It wants a maximum, this we want to see if the second derivative's profit at the end is negative.

A''\frac{4\sqrt{3}}{3} = -12\frac{4\sqrt{3}}{3}

8 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
4 years ago
Helppppp 10points plz
ale4655 [162]

What is the question?

6 0
4 years ago
Can anyone help me please
guajiro [1.7K]

Answer:

a) 5 people

b) Yes.

Step-by-step explanation:

The best way to solve this problem is to use the amount of work needed each week and divide it by the amount worked by each person (150/32). This will give you 4.6875. However, you cannot have 6/10 of a person, so you must round up to the next whole number, 5. There are 5 people needed to fulfill the amount of hours posted. For Part B, you will be decreasing the hours worked by each person from 32 to 30. Use the same method you did above and divide the total amount of work needed by the amount worked by each person (150/30) to get 5 on the dot. Your answer is Yes.

I hope this helps! Good luck!

6 0
3 years ago
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