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never [62]
3 years ago
13

Sofia got a raise, from an annual salary of $43,000 to $44,505. what percent was her raise?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

c) 3.5%

Step-by-step explanation:

First, determine the difference between their old and new salary:

$44,505 – $43,000 = $1,505

Next, divide the raise amount by the old salary:

$1,505 / $43,000 = . 035

To turn the decimal into a percentage, multiply by 100

0.35x100=3.5%

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A quadratic functions has zeros of 5 and -2. What could be the equation in factored form?
marusya05 [52]

Hi,

A is the  answer as   :    -2+2 = 0  and  5 -5 = 0

8 0
3 years ago
3/5 +9/10= Please answer<br>​
Art [367]

Answer:

3/2 or 1.5

Step-by-step explanation:

Multiply 3/5 by 2 to make the denominator of both fractions equal.

2 x 3/5 = 6/10

Now that the denominators are equal, add the two fractions together

6/10 + 9/10 = 15/10 = 3/2 or 1.5

4 0
3 years ago
Read 2 more answers
Consider functions f and g below.
Pani-rosa [81]

Answer:

D

Step-by-step explanation:

f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15)  Remove the brackets

f(x) - g(x) = -9x^2 - 7x  + 12 - 3x^2 + 4x + 15

f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15

f(x) - g(x) = -12x^2- 3x + 27

Answer D

3 0
4 years ago
Read 2 more answers
Please help thank you.
alina1380 [7]
Hello!

To solve this we use the equation sin60 = (s/2) / (d/2)

s is a side of the triangle
d is the diameter

sin60 = s/d

\sqrt{3/4} =s/d

d=s/ \sqrt{3/4}

d = s \sqrt{4/3}

d = 2s/ \sqrt{3}

put 6 in for s

d=12/ \sqrt{3}

d =  \sqrt{48}

d = 6.9

The answer is C) 6.9

Hope this helps!
5 0
3 years ago
4cos^2(x)-7cos(x)+3<br> Please help and explain how you did it :)
dangina [55]

I assume you're asked to solve

4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0

Factor the left side:

(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0

Then either

4 cos(<em>x</em>) - 3 = 0   <u>or</u>   cos(<em>x</em>) - 1 = 0

cos(<em>x</em>) = 3/4   <u>or</u>   cos(<em>x</em>) = 1

From the first case, we get

<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>

and from the second,

<em>x</em> = <em>nπ</em>

where <em>n</em> is any integer.

7 0
3 years ago
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