If a(x)=3x+1 and b(x)=square root x-4, what is the domain of (b o a)(x)?
2 answers:
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XY = 17.
Because YW is a perpendicular bisector, we can say that TW and WZ are both equal to 3. It tells us that XZ is 12, so that means that XW must be 12+3 which equals 15.
It also tells us that YW is 8. So we can use the Pythagorean Theorem to find the hypotenuse of Triangle XWY. Thus,
To solve this equation, square and add both of the terms on the right like this:
And then take the square root of both sides. Your final answer should be:
XY = 17.
Because YW is a perpendicular bisector, we can say that TW and WZ are both equal to 3. It tells us that XZ is 12, so that means that XW must be 12+3 which equals 15.
It also tells us that YW is 8. So we can use the Pythagorean Theorem to find the hypotenuse of Triangle XWY. Thus,
To solve this equation, square and add both of the terms on the right like this:
And then take the square root of both sides. Your final answer should be:
XY = 17.
The equation can be written in vertex form as
y = a(x +2)² - 3
Substituting the given values, we can find the coefficient "a".
-5 = a(-1+2)² -3
-2 = a . . . . . . . . . add 3 and simplify
The coefficient of the squared term is -2.
y = a(x +2)² - 3
Substituting the given values, we can find the coefficient "a".
-5 = a(-1+2)² -3
-2 = a . . . . . . . . . add 3 and simplify
The coefficient of the squared term is -2.