The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;



B₁ = 10², B₂ = 
Therefore;

The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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Answer:
answer is b just had this problem lol
Step-by-step explanation:
X/28 = 5/7
x = 28 * 5 / 7
x = 20
answer
x = 20 ft
(y+20)=1(x+10); First, we can find the slope by using the equation y2-y1/x2-x1.
-9+20/1+10 (Accounting for double negatives).
11/11 = 1
The slope of the equation is 1, now we just need to pick a set of points from which we derived the slope from (doesn't matter which) as y1 and x1 in the point-slope equation. (y-y1)=m(x-x1)
Your final answer can either be (y+20)=1(x+10) or (y+9)=1(x-1) but in the context of this question it is (y+20)=1(x+10)