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pshichka [43]
2 years ago
5

62.52=27.39+t this is 7th grade math! plsss help!!1

Mathematics
1 answer:
Tju [1.3M]2 years ago
6 0

Answer:

Hope it helps you friend

and please mark me as

BRAINLIEST

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Is the system of equations is consistent, consistent and coincident, or inconsistent?
kicyunya [14]
<span><span>Hiya!

Y=−3x+1
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2y=−6x+2

The answer is...

</span></span><span>consistent and coincident
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(If it Helps I took the test, its 100% Right)
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3 years ago
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gulaghasi [49]
I think the answer is C 1 2/3
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3 years ago
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You practice playing your guitar every day. You spend 15 minutes practicing chords and the rest of the time practicing a new son
Black_prince [1.1K]

Answer:

<h2>x=(y-105)/7</h2>

Step-by-step explanation:

Given that the total time taken to practice is given by the expression as

y=7(15+x)

Simplifying the expression we have

y=105+7x

Solving for x (that is making x subject of formula we have)

7x=y-105

Divide both sides by 7 we have

x=(y-105)/7

Therefore the expression is

x=(y-105)/7

5 0
3 years ago
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
3 years ago
A screening test for a certain disease is used in a large population of people of whom 1 in 1000 actually have the disease. Supp
sertanlavr [38]

Answer:

P(D/T)=5.05*10^{-6}

Step-by-step explanation:

Let's call D the event that a person has the disease, D' the event that a person doesn't have the disease and T the event that the person tests negative for the disease.

So, the probability P(D/T) that a randomly chosen person who tests negative for the disease actually has the disease is calculated as:

P(D/T) = P(D∩T)/P(T)

Where P(T) = P(D∩T) + P(D'∩T)

So, the probability P(D∩T) that a person has the disease and the person tests negative for the disease is equal to:

P(D∩T) = (1/1000)*(0.005) = 0.000005

Because 1/1000 is the probability that the person has the disease and 0.005 is the probability that the person tests negative given that the person has the disease.

At the same way, the probability P(D'∩T) that a person doesn't have the disease and the person tests negative for the disease is equal to:

P(D'∩T) = (999/1000)*(0.99) = 0.98901

Finally, P(T) and P(D/T) are equal to:

P(T) = 0.000005 + 0.98901 = 0.989015

P(D/T) = 0.000005/0.989015 = 5.05*10^{-6}

8 0
2 years ago
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