<span><span>Hiya!
Y=−3x+1
</span><span>
2y=−6x+2
The answer is...
</span></span><span>consistent and coincident
</span>
Hope This Helps!
(If it Helps I took the test, its 100% Right)
(Brainliest is always appreciated)
If You Have Any More Questions Feel Free To Ask! :)
I think the answer is C 1 2/3
Answer:
<h2>x=(y-105)/7</h2>
Step-by-step explanation:
Given that the total time taken to practice is given by the expression as
y=7(15+x)
Simplifying the expression we have
y=105+7x
Solving for x (that is making x subject of formula we have)
7x=y-105
Divide both sides by 7 we have
x=(y-105)/7
Therefore the expression is
x=(y-105)/7
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The capacity of the metal tank is 
The duration usage is 
The cost of 2000-gallon tank 15 years ago is 
The capacity of the second tank considered is
The power sizing exponent is 
The initial construction cost index is 
The new construction after 15 years cost index is 
Equation for the power sizing exponent is mathematically represented as
![\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}](https://tex.z-dn.net/?f=%5Cfrac%7BP_n%7D%7BP%7D%20%3D%20%5B%5Cfrac%7BC_1%7D%7BC%7D%20%5D%5E%7Be%7D)
=> Here
is the cost of 5,000-gallon tank as at 15 years ago
So
![P_n = [\frac{5000}{2000} ] ^{0.57} * 100000](https://tex.z-dn.net/?f=P_n%20%20%3D%20%20%5B%5Cfrac%7B5000%7D%7B2000%7D%20%5D%20%5E%7B0.57%7D%20%2A%20100000)

Equation for the cost index exponent is mathematically represented as

Here
is the cost of 5,000-gallon tank today
So

=> 
=> 
Answer:

Step-by-step explanation:
Let's call D the event that a person has the disease, D' the event that a person doesn't have the disease and T the event that the person tests negative for the disease.
So, the probability P(D/T) that a randomly chosen person who tests negative for the disease actually has the disease is calculated as:
P(D/T) = P(D∩T)/P(T)
Where P(T) = P(D∩T) + P(D'∩T)
So, the probability P(D∩T) that a person has the disease and the person tests negative for the disease is equal to:
P(D∩T) = (1/1000)*(0.005) = 0.000005
Because 1/1000 is the probability that the person has the disease and 0.005 is the probability that the person tests negative given that the person has the disease.
At the same way, the probability P(D'∩T) that a person doesn't have the disease and the person tests negative for the disease is equal to:
P(D'∩T) = (999/1000)*(0.99) = 0.98901
Finally, P(T) and P(D/T) are equal to:
P(T) = 0.000005 + 0.98901 = 0.989015
