Remember (a²-b²)=(a-b)(a+b)
solve for a single variable
solve for y in 2nd
add y to both sides
x²-7=y
sub (x²-7) for y in other equaiton
4x²+(x²-7)²-4(x²-7)-32=0
expand
4x²+x⁴-14x²+49-4x²+28-32=0
x⁴-14x²+45=0
factor
(x²-9)(x²-5)=0
(x-3)(x+3)(x-√5)(x+√5)=0
set each to zero
x-3=0
x=3
x+3=0
x=-3
x-√5=0
x=√5
x+√5=0
x=-√5
sub back to find y
(x²-7)=y
for x=3
9-7=2
(3,2)
for x=-3
9-7=2
(-3,2)
for √5
5-7=-2
(√5,-2)
for -√5
5-7=-2
(-√5,-2)
the intersection points are
(3,2)
(-3,2)
(√5,-2)
(-√5,-2)
Answer:
x=-11, -1, and 3
Step-by-step explanation:
x^3+9x^2-25x-33=0
There are formulas to solve cubics, but that probably is not the way you are expected to go. Here is a trial and error approach that works in this case.
Assume that the cubic can be factored and that the roots are r1, r2, and r3. Then the factored form is
(x-r1)(x-r2)(x-r3)=0
This shows that the constant must equal the product of the roots.
(r1)(r2)(r3)=-33
One possibility is that the roots are integers. In this case, a factor of 33 might work. Prime factorization of 33 gives 3 and 11. Try 3. Then (x-3) is a factor.
Divide the cubic by (x-3). It works. the result is
x^2+12x+11
This has factors of (x+11) and (x+1). Therefore, the roots are 3, -1, and -11
Please Mark brainliest
Riemann sums help us approximate definite integrals, but they also help us formally define definite integrals. Learn how this is achieved and how we can move between the representation of area as a definite integral and as a Riemann sum.
Definite integrals represent the area under the curve of a function, and Riemann sums help us approximate such areas. The question remains: is there a way to find the exact value of a definite integral?
You can find some reference below:
https://math.wvu.edu/~hlai2/Teaching/Tip-Pdf/Tip1-29.pdf
