Let the fist integer be x, the second is x+20
the product of the numbers is:
x(x+20)
the sum of the numbers is:
x+x+20=2x+20
the sum of the above operations will give us:
2x+20+x^2+20x=95
x^2+22x+20=95
this can be written as quadratic to be:
x^2+22x-75=0
solving the above we get:
x=3 and x=-25
but since the integers should be positive, then x=3
the second number is x+20=3+20=23
hence the numbers are:
3 and 23
Answer:
2.25
Step-by-step explanation:
because you have to divide 32 by 14 2/9 resulting in the the 14 2/9 to be 128/9 and then flipped, 9/128. Afterwards, cross out the the 32 and 128 since 32 is a factor of 128 to get 1 and 4.Then apply mutiplication 1/1 * 9/4= 9/4 or 2 1/4= 2.25
5892 divided by 18 is 327 rounded
Answer:
Step-by-step explanation:
This is a problem of SETS.
Start by listing out important data:
1. Total that said F = 55
2. Total that said P = 51
3. Total that said O = 61
4. F only = 9
5. F ∩ P ∩ O = 26 [NOTE: If you were to draw a Venn Diagram, 26 would be in the innermost circle because it comprises all three categories]
6. F ∩ P = 31
7. P only = 8
8. Students that said none of the 3 reasons = 4
QUESTIONS
1. How many said O and P? In other words, find the intersect of O and P. Find O ∩ P
2. How many said either F or O? [Answer to be gotten using a venn diagram] Find F ∪ P which translates to "F union P"
3. How many said F without saying P? [Answer to be gotten from the venn diagram as well]
4. How many students in total were surveyed? [HINT: Remember to include the 4 students that had none of the three options]
The answer might be 18x^2+19x+35