Since perpendicular lines have their slopes as negative reciprocals, the negative reciprocal of the given slope (3) is -1/3. Therefore the a value is -1/3.
Answer:
m = -1/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
9m - m + 3 = -2(m + 1)
<u>Step 2: Solve for </u><em><u>m</u></em>
- Combine like terms: 8m + 3 = -2(m + 1)
- Distribute -2: 8m + 3 = -2m - 2
- Add 2m on both sides: 10m + 3 = -2
- Isolate <em>m</em> term: 10m = -5
- Isolate <em>m</em>: m = -1/2
Jessica pays a membership fee of $40
so that's given to us
<span>Jessica has a membership fee of $40 (given)
Nancy has a membership fee of $30 (y intercept of the equation)
</span>so how much is jessica going to pay is $10 more than Nancy
Answer:
B) Graph B only.
Step-by-step explanation:
Table A is not correct, because:
In Y = 2X, replacing each row:
3 =/= 2 x 2
6 =/= 2 x 4
9 =/= 2 * 6
Table B is correct, because:
When Y is 2, X is 1 which is equal to 2x1.
When Y is 4, X is 2 which is equal to 2x2.
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
