Given:
A line through the points (7,1,-5) and (3,4,-2).
To find:
The parametric equations of the line.
Solution:
Direction vector for the points (7,1,-5) and (3,4,-2) is
Now, the perimetric equations for initial point with direction vector
, are
The initial point is (7,1,-5) and direction vector is . So the perimetric equations are
Similarly,
Therefore, the required perimetric equations are and
.
Answer:
x = - 5, x = 2
Step-by-step explanation:
Using the rules of logarithms
log x - log y = log ( )
x = n ⇔ x =
note that log x = x
Given
log (x² + 3x) - log10 = 0, then
log( ) = 0, thus
=
= 1 ( multiply both sides by 10 )
x² + 3x = 10 ( subtract 10 from both sides )
x² + 3x - 10 = 0 ← in standard form
(x + 5)(x - 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
x - 2 = 0 ⇒ x = 2
Solution is x = - 5, x = 2