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allochka39001 [22]
3 years ago
14

Describe the end behavior of f(x)=10x^4

Mathematics
1 answer:
Reika [66]3 years ago
5 0
<span>I think when you ask me to describe the end behavior of f(x)=10x^4 you mean for me to answer like this 10^4=10,000.</span>
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Write a subtraction expression using integers that equals -6.
pochemuha

Answer:

-9 minus -3

Step-by-step explanation:

-9 - (-3) = -9 + 3 = -6

Subtract and keep the sign of the bigger number.

8 0
3 years ago
Find the missing angle. <br> Select one:<br><br> 85°<br><br> 180°<br><br> 158°<br><br> 32°
Fed [463]

Answer:

missing angle 32 ...........

5 0
3 years ago
HELP HURRY
WINSTONCH [101]
The first option is the answer, it is going from P to Q so the only logical answer would be the first choice
7 0
3 years ago
Graphs of Function,
andrew-mc [135]

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

<u>Question 7</u>

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

(- \infty,-2)

The function is decreasing when x > -2

(-2, \infty)

<u>Additional information</u>

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

f(x)=-2x^2-8x-8

\implies f'(x)=-4x-8

The function is increasing when f'(x) > 0

\implies -4x-8 > 0

\implies -4x > 8

\implies x < -2

The function is decreasing when f'(x) < 0

\implies -4x-8 < 0

\implies -4x < 8

\implies x > -2

This concurs with the observations made from the graph.

<u>Question 8</u>

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

(- \infty,+ \infty)

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

[-4,1]

<u>Question 9</u>

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

(- \infty,-1)

The function is increasing when x > -1

(-1, \infty)

5 0
1 year ago
Prove that 3999991 is not prime
rodikova [14]

3999991=4000000-9=2,000^2-3^2=(2000-3)(2000+3)=1997\cdot2003

As we can see, the number 3999991 can be expressed as a product of two numbers that are not 1 and the number 3999991 itself, therefore that number is not prime.

7 0
3 years ago
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