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Tatiana [17]
2 years ago
10

Help please asap??????

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0
18ft because each side is being times by 2
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Find the median, first quartile, third quartile, and interquartile range of the data.
jasenka [17]

Answer:

Median: 55

First quartile: 26.5

Third quartile: 93

Interquartile range: 66.5

5 0
2 years ago
Read 2 more answers
Help Me Please!!!!1
Lena [83]

Answer:

The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.

Step-by-step explanation:

Here we have the volume of the cube box given by the following relation;

Volume of cube = Length. L × Breadth, B × Height, h

However, in a cube  Length. L =  Breadth, B = Height, h

Therefore, volume of cube = L×L×L = 13³ = 2197 in³

Volume of the basketball is given by the volume of a sphere as follows;

Volume = \frac{4}{3} \pi r^3

Where:

r = Radius = Diameter/2 = 14/2 = 7in

∴ Volume of the basketball = \frac{4}{3} \times  \pi \times 7^3 = 1436.76 \ in^3

Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;

The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.

7 0
3 years ago
What is the length of the hypotenuse? If necessary, round to the nearest tenth.
azamat

By the Pythagorean theorem,

a^{2}+12^{2}=13^{2}\\\\a^{2}+144=169\\\\a^{2}=25\\ \\ a=\boxed{5}

4 0
2 years ago
If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0
1 year ago
At 2pm the level of the water in the pool was 10 feet. At 6pm the level of water was 2 feet. Find the constant rate of the water
adelina 88 [10]
Assuming that the pool was drained at a constant rate, the speed at which it was drained can be expressed as a function of time. In this case, the pool level will be expressed in feet per hour.

The time changed by 4 hours (6-2), and the level of the pool changed by -8 feet (2-10). Diving the feet by the hours to get the rate of decreasing depth, we find that the rate equals -2 feet/hour.
7 0
3 years ago
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