Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
(C)81
Step-by-step explanation:
Total Number of Students =300
Percentage who had cats, n(C) = 40%
Percentage who had both cats and dogs ,
= 12%
Percentage who had neither cats nor dogs,
=45%
Now:
Universal Set, 

Therefore:
Number of Students who had dogs
=27% of 300
=81
Answer:
4.78x
Step-by-step explanation:
how've 7,.8*x 3n by 6y is =4.78x
Answer: Pt1= Only x=5
Pt2=Is not x=5 is an extraneous solution though I believe It is x=-2 is an extraneous solution
Step-by-step explanation:
To find the answer just divide the length of a flower garden by the length of a brick:
11.25 / 0.25 = 45 (that's how many bricks are needed to be put).
There's nothing to round, but you can write it as a decimal to the hundredth place as 45.00.