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Delicious77 [7]
3 years ago
9

Write the equation in slope intercept form. what are the slope and y intercept -2x-11y=5.

Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

-11y = 2x + 5 is your answer.

Step-by-step explanation:

The slope-intercept form is y = mx + b.

-11y = y

-2x = the slope

5 = b.

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2 years ago
With a short time remaining in the​ day, a delivery driver has time to make deliveries at 4 locations among the 7 locations rema
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Answer:

35 different routes

Step-by-step explanation:

The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.

Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.

The number of combinations of n objects taken r at a time is: ⁿCᵣ

So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by

⁷C₄ = 35 different ways.

Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.

Hope this Helps!!!

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3 years ago
Find the common difference of the arithmetic<br> sequence 4, 10, 16,
DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the nature of the root
GREYUIT [131]

Answer:

1) Real and same.

2) Real and distinct

3) Real and distinct

4) Real and distinct

5) Real and distinct

6) Real and distinct

7) Real and distinct

8) Real and distinct

Step-by-step explanation:

If a quadratic equation is in the form of ax² + bx + c = 0, then Discriminant of the equation D = b² - 4ac, which governs the nature of roots the equation has.

If D > 0, then there will be two different real roots.

If D = 0, then two same and real roots.

If D < 0, then two distinct but imaginary roots.

Now, 1) x² + 6x + 9 = 0 has D = 6² - 4 × 9 × 1 = 0. So, there will be two same and real roots.

2) 5x² - x = 4x² + 2

⇒ x² - x - 2 = 0

It has D = (-1)² - 4 × 1 × (-2) = 9. Therefore, the roots will be two distinct and real.

3) \frac{2}{x} + \frac{3}{x} = x - 4

⇒ 5 = x² - 4x

⇒ x² - 4x - 5 = 0.

So, D = (-4)² - 4 × (1) × (- 5) = 36. So, the equation has two real and distinct rools.

4) x(x - 5) = 4(5 - x)

⇒ x² - x - 20 = 0

Hence, D = (-1)² - 4 × 1 × (-20) = 81

So, the roots will be real and distinct.

5) x² + 7x + 1 = 0 has D = 7² - 4 × 1 × 1 = 45

So, the roots will be real and distinct.

6) 2x² + 9x + 3 = 0, has D = 9² - 4 × 2 × 3 = 57.

Hence, the roots will be real and distinct.

7) 5x² - 6 = 13x

⇒ 5x² - 13x - 6 = 0

So, D = (-13)² - 4 × 5 × (-6) = 289

So, the roots will be real and distinct.

8) x² - x = 3(x + 7)

⇒ x² - 4x - 21 = 0

It has D = (-4)² - 4 × 1 × (-21) = 100

So, the roots will be real and distinct. (Answer)

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3 years ago
How to find algebraic expressions using a table of values
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I think that the answers is b
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