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2 years ago

Math 201 Statistics week 6 discussion board?

Mathematics

1 answer:

rjkz [21]2 years ago

7 0

Answer: ??? What

Explanation: what’s the question??

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X^2+3x-10 will be zero when x equals

Anit [1.1K]

Answer:

Answer: x equals to 2 and -5

Step-by-step explanation:

${ \tt{ {x}^{2} + 3x - 10 = 0 }}$

» Factorise the equation quadratically:

${ \tt{(x - 2)(x + 5) = 0}} \\ { \tt{x = 2 \: \: and \: \: - 5}}$

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2 years ago

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Nady [450]

Answer:

1 $\frac{3}{4}$

Step-by-step explanation:

To find the answer, we divide the number of apples by the number of bags. This means we do 7 ÷ 4

7 ÷ 4 = 1.75

1.75 in fraction form is 1 $\frac{3}{4}$

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2 years ago

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I will mark u as the brainiest if u get this correct thx x

Sergeu [11.5K]

Answer:

Step-by-step explanation:

9cm? I'm very sorry if i got this wrong <3

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2 years ago

Solve for x 45 degrees 90 degrees 65 degrees 85 degrees

Mrrafil [7]

Answer:

x = 45

Step-by-step explanation:

x and (90 - x) are alternate exterior angles and are congruent , then

x = 90 - x ( add x to both sides )

2x = 90 ( divide both sides by 2 )

x = 45

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10 months ago

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Rewrite 2tan3x in terms of tanx

blsea [12.9K]

$2\tan3x=2\tan(2x+x)=\dfrac{2\tan2x+2\tan x}{1-\tan2x\tan x}$

Use the same identity to expand $\tan2x$ .

$\tan2x=\tan(x+x)=\dfrac{\tan x+\tan x}{1-\tan x\tan x}=\dfrac{2\tan x}{1-\tan^2x}$

$\implies2\tan3x=\dfrac{2\dfrac{2\tan x}{1-\tan^2x}+2\tan x}{1-\dfrac{2\tan x}{1-\tan^2x}\tan x}$
$2\tan3x=\dfrac{2\tan x\left(\dfrac2{1-\tan^2x}+1\right)}{1-\dfrac{2\tan^2x}{1-\tan^2x}}$
$2\tan3x=\dfrac{2\tan x\left(2+1-\tan^2x\right)}{1-\tan^2x-2\tan^2x}$
$2\tan3x=\dfrac{2\tan x(3-\tan^2x)}{1-3\tan^2x}$

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3 years ago