Answer:x = 1
y = 1
Step-by-step explanation:
The given system of simultaneous equations is expressed as
3x - 5y = - 2 - - - - - - - - - - - - 1
2x + y = 3 - - - - - - - - - - - - - 2
The first step is to decide on which variable to eliminate. Let us eliminate x. Then we would multiply both rows by numbers which would make the coefficients of x to be equal in both rows.
Multiplying equation 1 by 2 and equation 2 by 3, it becomes
6x - 10y = - 4
6x + 3y = 9
Subtracting, it becomes
- 13y = - 13
y = - 13/- 13 = 1
The next step is to substitute y = 1 into any of the equations to determine x.
Substituting y = 1 into equation 2, it becomes
2x + 1 = 3
2x = 3 - 1 = 2
x = 2/2 = 1
Answer:
-1 < x < 4.
Step-by-step explanation:
- 6 < 2x - 4 <4
2x - 4 < 4
2x < 8
x < 4. Also we have:
2x - 4 > -6
2x > -2
x > -1.
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2