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baherus [9]
3 years ago
15

111,111,111×111,111,111

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

1.2345679e+16

Step-by-step explanation:

Andrej [43]3 years ago
5 0

Answer:

Step-by-step explanation:

Can i be made brainliest

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8 dolors is the correct answer
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yes i do :)

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PLZZZZ HELP WILL MARK BRAINLIEST
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5 0
3 years ago
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The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece
nlexa [21]

Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

You feel that a reasonable estimate of the standard deviation is 10.0 hours.

This means that \sigma = 10

What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?

A sample size of n is needed. n is found when M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.96\frac{10}{\sqrt{n}}

\sqrt{n} = 1.96*10

(\sqrt{n})^2 = (1.96*10)^2

n = 384.16

Rounding up:

A sample size of 385 is needed.

7 0
3 years ago
Simplify to create to an equivalent expression 8k−5(−5k+3)
Alexeev081 [22]

Answer:

33k - 15

Step-by-step explanation:

=> 8k-5(-5k+3)

=> 8k+25k-15

=> 33k - 15

6 0
3 years ago
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