"Given : a survey was conducted in a group of 100 students of a school. the ratio of students who like mathematics and computer is 3:5. if 30 of them like both subjects and 10 of them like none of them,
To Find : number of students who like: at most one subject.
Solution:
Mathematics = 3k
Computer = 5k
30 of them like both subjects
10 of them like none of them
Total = Math + Computer - Both + None
100 = 3k + 5k - 30 + 10
=> 120 = 8k
=> k = 15
Mathematics = 45
Computer = 75
Mathematics only = Mathematics - Both = 45 - 30 = 15
Computer only = Computer - Both =75 - 30 = 45
at most one subject = 100 - Both subjects 100 - 30 = 70
or none + computer only + Mathematics only = 10 + 45 + 15 = 70
70 Students like at most one subject"
Let's say the larger number is x. that means that the smaller number is x - 3. since you know their sum is x + x - 3, and that is equal to 14. so you have the equation x + x - 3 = 14. combine like terms (x) to get 2x - 3 = 14. add three to both sides to get 2x = 17. divide both sides by two to get x = 17/2. so the larger number is 17/2, and the larger number is 11/2 (17/2 - 3 = 11/2)
(y+2)(y-2)=y²-4
3y²+8y-16-?=y²-14
add ? to both sides
3y²+8y-16=y²-14+?
minus y² both sides and add 14
2y²+8y-2
the quantity was 2y²+8y-2
Answer:
The statement is True!
Step-by-step explanation:
Clare paid full price for an item.
Let Price of the item = x
Han bought the same item for 80% of the full price.
Han bought it for 0.8x
Clare said, I cants believe I paid 125% of what you paid, Han!
The above statement is True if;
125% of 0.8x = x
1.25 * 0.8x = x
x =x
The statement is True!
Answer: 3x+6 = 2(x+6)
Step-by-step explanation:
Ralph's age: y; Sara's age: x
Ralph is 3 times as old as Sara: y = 3x
In 6 years, Ralph will be only twice as old as Sara will be then: (y+6) = 2(x+6)
Substitute y=3x into (y+6) = 2(x+6).
3x+6 = 2(x+6)