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2 years ago

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Mathematics

1 answer:

Artist 52 [7]2 years ago

7 0

Answer:

Read explain

Step-by-step explanation:

The steps taken to solve this system of equations would first be:

1. Sub 4x-2 into your first equation, 2x+5(4x-2)= 12 ->

2. Solve/simplify this equation to get x=1

3. Sub x=1 into your second equation and solve for y = 2

4. Get the solution (1,2)

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borishaifa [10]

Answer:

10 = 2y + 4

6 = 2y

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Step-by-step explanation:

18 = 10 + 2x

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3 years ago

1. Expresa cada función cuadrática f en la forma f(x)-yo = p(x – xo) x ϵ R, donde xo , yo , p ϵ R son elegidos apropiadamente. I

crimeas [40]

Answer:

Step-by-step explanation:

1. Express each quadratic function f in the form f (x) -yo = p (x - xo) x ϵ R, where xo, i, p ϵ R are appropriately chosen. Indicate the coordinates

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3 years ago

Help on math please!

DedPeter [7]

(13•4) + (3•8) +3 = 79
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3 years ago

The volume of the rectangular prism is 60x^3 + 145x^2 + 70x. Factor to find the possible expressions for length, width and heigh

tester [92]

The volume of the rectangular prism:
$V=length\cdot width\cdot height=lwh$

$60x^3 + 145x^2 + 70x=5x(12x^2+29x+14)\\\\=5x(12x^2+21x+8x+14)=5x[3x(4x+7)+2(4x+7)]\\\\=5x(4x+7)(3x+2)\\\\Answer:\\length=5x\\width=4x+7\\height=3x+2$

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3 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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3 years ago