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user100 [1]
3 years ago
15

What was the rule used for the composite transformation?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0
(x, y) → (x + 1, y + 5)
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A brand new filled jar of salsa is 11 cm tall and a has a radius of 6 cm. Kelly eats some of the salsa and the salsa in the jar
Sonbull [250]

Before we begin please note that a jar is always cylindrical in shape if not mentioned otherwise. Thus, we will take a cylindrical jar in this case.

Since Kelly eats some of the salsa and the salsa in the jar is now 6 cm high, we know that Kelly ate the amount of Salsa whose volume is missing from the jar.

To find the missing volume on the Salsa jar all that we need to do is to find the height of the missing volume which is given to us as h= 6 cm. We already know that the radius of the jar, r=6 cm. Thus, the amount of Salsa Kelly has eaten is:

V=\pi(6)^2\times 6\approx678.6\approx679 cm^3

Thus, the third option is the correct answer

8 0
3 years ago
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Ursula says the distance between -5.47 and 5.47 on a number line is equal to |-5.47|. explain her error
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Your absolute value cannot be negative.
5 0
2 years ago
Can you name some math terms starting with the letter "O" and give a short description of them?
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Obtuse angle

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2 years ago
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The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
Yeah i need major help with this
Lady_Fox [76]

Answer:

See below

Step-by-step explanation:

I'm not sure if there are any specific instructions on how these answers are supposed to be written, but here's my best shot:

1. U

2. XZ, VY

3. VU, WU

4. XY, ZY

5. ⊙U

6. XZ, VY (they are diameters but also intersect)

7. VY = 10 cm, WU = 5 cm

8. Diameter (of larger circle)

9. Diameter (of smaller circle)

10. Radius (of larger circle)

11. Radius (of smaller circle)

3 0
2 years ago
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