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3 years ago

13

X^2 + x^2=6^2 what is x

2 answers:

nikitadnepr [17]3 years ago

5 0

Answer:

x = ±3 sqrt(2)

Step-by-step explanation:

x^2 + x^2=6^2

Combine like terms

2x^2 = 6^2

Divide each side by 2

x^2 = * 6^2/2

Take the square root of each side

sqrt(x^2) =± sqrt( 6^2/2)

Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)

x = ±sqrt(6^2)/sqrt(2)

x = ±6 /sqrt(2)

We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)

x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)

x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))

x = ±6 sqrt(2) /(2)

x = ±3 sqrt(2)

Dmitrij [34]3 years ago

3 0

Answer:

x=±3sqrt2

Step-by-step explanation:

<em>6^2=36</em>

36=2(±x^2)

<em>/2 /2</em>

18=±x^2

<em>sqrt sqrt</em>

sqrt18=x

sqrt18=±3sqrt2

±3sqrt2=x

or

x=±3sqrt2

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3 0

3 years ago

!!!please for the love of God help me!!!

Grace [21]

<h3>Given :-</h3>

$\\$

x=y-1
x+2y=8

$\\$

<h3>To find:</h3>

$\\$

Value of x
Value of y

$\\$

<h3>Solution:-</h3>

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

$\\ \\$

Simplifying 1 equation:-

x = y - 1
x +1 = y
y = x + 1

Put this value of y in second equation.

$\\$

$\dashrightarrow \sf \: x+2y=8$

$\\$

$\dashrightarrow \sf \: x+2(x + 1)=8$

$\\$

$\dashrightarrow \sf \: x+2x +2=8$

$\\ \\$

$\dashrightarrow \sf \: 3x +2=8$

$\\ \\$

$\dashrightarrow \sf \: 3x=8 - 2$

$\\ \\$

$\dashrightarrow \sf \: 3x=6$

$\\ \\$

$\dashrightarrow \sf \: x=6 \div 3$

$\\ \\$

$\dashrightarrow \sf \: x= \bf2$

$\\$

to find value of y :-

y = x + 1

y = 2 + 1

y = 3

$\\$

verification:-

$\\$

1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

$\\$

2 equation:-

$\\$

x+2y=8

put value of x and y

2 + 2 × 3 = 8
2 + 6 = 8
8 = 8

LHS = RHS

Hence verified!

$\\$

Both equation verified!

.°. value of x and y is 2 and 3 respectively

7 0

2 years ago