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Akimi4 [234]
4 years ago
13

X^2 + x^2=6^2 what is x​

Mathematics
2 answers:
nikitadnepr [17]4 years ago
5 0

Answer:

x = ±3 sqrt(2)

Step-by-step explanation:

x^2 + x^2=6^2

Combine like terms

2x^2 = 6^2

Divide each side by 2

x^2 = * 6^2/2

Take the square root of each side

sqrt(x^2) =± sqrt(  6^2/2)

Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)

x = ±sqrt(6^2)/sqrt(2)

x = ±6 /sqrt(2)

We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)

x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)

x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))

x =  ±6 sqrt(2) /(2)

x = ±3 sqrt(2)

Dmitrij [34]4 years ago
3 0

Answer:

x=±3sqrt2

Step-by-step explanation:

<em>6^2=36</em>

36=2(±x^2)

<em>/2       /2</em>

18=±x^2

<em>sqrt sqrt</em>

sqrt18=x

sqrt18=±3sqrt2

±3sqrt2=x

or

x=±3sqrt2

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tresset_1 [31]

Answer:

A is 10.0 inches.

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Step-by-step explanation:

To find the answers, we can just multiply our original lengths by our scale factor.

Our original width is 8 inches.

This means that our new width, A, will be our old width multiplied by our scale factor.

So:

A=8(1.25)=10\text{ inches}

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3 years ago
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A computer can be classified as either cutting dash edge or ancient. Suppose that 86​% of computers are classified as ancient. ​
andrezito [222]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86​% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

P(ancient)=0.86

(a) To find the probability that two computers are chosen at random and both are ancient​ you must,

The probability that the first computer is ancient is P(ancient)=0.86 and the probability that the second computer is ancient is P(ancient)=0.86

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396

(b) To find the probability that seven computers are chosen at random and all are ancient​ you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge​ you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

P(C)=1-P(A)=1-0.3479=0.6520

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0
3 years ago
7. Find the length of AB<br> please answer will mark brainelist :)
Julli [10]

Answer:

A) 17 m  B) 20.8 m

Step-by-step explanation:

I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11

26-11 = 15

I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)

AB is the hypotenuse

We can use the pythagorean theorem  to find length AB (a^2 + b^2 = c^2)

a and b is the legs which is 8 and 15

8^2 + 15^2 = AB^2

64 + 225 = AB^2

289 = AB^2

√289 = AB (to undo a square, you use square roots)

√289 = 17

AB = 17 m

Now we need to find the hypotenuse of AC

the same thing, we did for problem A, use the pythagorean theorem

17^2 + 12^2 = AC^2

289 + 144 = AC^2

433 = AC^2

√433 = AC

√433 is <em>about </em>20.808...

round to the tenth as stated in the directions

AC = 20.8 m

7 0
2 years ago
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