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Rainbow [258]
3 years ago
5

How do you do answer these math question I got confused

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
The first one I THINK is 21 and the second one I THINK is 20. I'm not sure though sorry if I'm wrong
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Which real-world scenario involves a right triangle?
alexira [117]
Putting a ladder up against a straight wall. The sides of the triangle are:
1: the ladder
2: the walls
3: the ground from the wall to the ladder
5 0
3 years ago
Y=3/4 x-4
pochemuha

Answer:

see graph of y=3/4 x-4

Step-by-step explanation:

Assuming you mean

y = \frac34x - 4

Below is a graph of that one. The slope is 3/4 and the interception with the y axis is at y=-4. The equation is in its normal form y=ax+b with a=3/4 (slope) and b=-4 (y intercept), so no conversion needed.

You have to be careful on how you write these equations down. It might very well be that you meant:

y = \frac{3}{4x-4} or y = \frac{3}{4x} - 4

However, those are more complex so I'm hoping for the first one... ;-)

8 0
3 years ago
What is 75% of 162? Show your work and/or explain your reasoning.
zhannawk [14.2K]

Answer:

121.5

Step-by-step explanation:

75% =  75/100

Step 2 - Mutiply percenatge fraction by the entire (100%) quantity

75/100× 162 = 121.5

Final result

75 percent of 162 is 121.5

3 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Ctext%7BQuestion%7D%7D%20%3A%20" id="TexFormula1" title=" \underline{ \
Oliga [24]

Answer:

Part A)

The height of the water level in the rectangular vessel is 2 centimeters.

Part B)

4000 cubic centimeters or 4 liters of water.

Step-by-step explanation:

We are given a cubical vessel that has side lengths of 10cm. The vessel is completely filled with water.

Therefore, the total volume of water in the cubical vessel is:

V_{C}=(10)^3=1000\text{ cm}^3

This volume is poured into a rectangular vessel that has a length of 25cm, breadth of 20cm, and a height of 10cm.

Therefore, if the water level is h centimeters, then the volume of the rectangular vessel is:

V_R=h(25)(20)=500h\text{ cm}^3

Since the cubical vessel has 1000 cubic centimeters of water, this means that when we pour the water from the cubical vessel into the rectangular vessel, the volume of the rectangular vessel will also be 1000 cubic centimeters. Hence:

500h=1000

Therefore:

h=2

So, the height of the water level in the rectangular vessel is 2 centimeters.

To find how how much more water is needed to completely fill the rectangular vessel, we can find the maximum volume of the rectangular vessel and then subtract the volume already in there (1000 cubic centimeters) from the maximum volume.

The maximum value of the rectangular vessel is given by :

A_{R_M}=20(25)(10)=5000 \text{ cm}^3

Since we already have 1000 cubic centimeters of water in the vessel, this means that in order to fill the rectangular vessel, we will need an additional:

(5000-1000)\text{ cm}^3=4000\text{ cm}^3

Sincer 1000 cubic centimeters is 1 liter, this means that we will need four more liters of water in order to fill the rectangular vessel.

3 0
3 years ago
Read 2 more answers
Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 60°. Find m∠Y.
hodyreva [135]

Answer:

m∠Y=50°

Step-by-step explanation:

So, we know that ∠S+∠Y=90 and that m∠S=2(m∠Y)-60.

If you plug those things into the equation, you get (2[m∠Y]-60)+m∠Y=90.

Then you multiply 2 and m∠Y: 2m∠Y-60+m∠Y=90.

Combine like terms: 3m∠Y-60=90.

Then you add 60 to both sides: 3m∠Y=150

Divide 3 on both sides: 3∠Y=50

7 0
3 years ago
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