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3 years ago

How do you do answer these math question I got confused

Mathematics

1 answer:

Sladkaya [172]3 years ago

4 0

The first one I THINK is 21 and the second one I THINK is 20. I'm not sure though sorry if I'm wrong

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Pizza is available with three kinds of cheese and four toppings. how many different ways can you order your pizza with one type

e-lub [12.9K]

You will choose 1 cheese 3 different ways because there are three types of cheeses.

You will choose your topings 6 different ways. 4!/(2!2!) = 4*3/2 = 6

Therefore you will be able to get 6 * 3 different pizzas = 18 pizza combinations.

To confirm the toppings, suppose they are (M)ushrooms (P)epperoni (O)nions and (B)acon

M P
M O
M B
P O
P B
O B

Total 6.The order doesn't matter here. M O is the same thing as OM

8 0

3 years ago

Ksenya-84 [330]

The answer is. f(x) 2x+6

3 0

2 years ago

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

3 years ago

If Pay(hours) is the function that describes Al's monthly pay at BIT Labs based on his training, Pay(22 hours), Pay(22), and P(2

maw [93]

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</span>

3 0

3 years ago

What is the average rate of change between f (1) and f (5) in the function f (x) = x2 - x - 6 ?

NISA [10]

Answer:

${ \tt{average = \frac{f(1) + f(5)}{2} }} \\ \\ = { \tt{ \frac{( {1}^{2} - 1 - 6) + ( {5}^{2} - 5 - 6) }{2} }} \\ = \frac{ - 6 + 14}{2} \\ \\ = { \tt{4}}$

5 0

3 years ago