Answer:
Cost of small box = $13
Cost of large box = $18
Step-by-step explanation:
Let the cost of small box of candy = $s
And the cost of large candy box = $b
Beth sold 9 small and 10 large boxes of candies for $297.
9s + 10b = 297 -----(1)
Sarah sold 8 small and 5 large boxes of candies for $194.
8s + 5b = 194 -------(2)
Multiply equation (2) by 2 then subtract equation (1) from (2).
2(8s + 5b) - (9s + 10b) = (2×194) - 297
16s + 10b - 9s - 10b = 388 - 297
7s = 91 ⇒ s = $13
From equation (2),
(8×13) + 5b = 194
104 + 5b = 194
5b = 90
b = $18
Answer:
Step-by-step explanation:
Taking the base 2 log of both sides, we get:
log-base 2 of 2 + log-base 2 of y = log-base 2 of 5, or
2 + log-base 2 of y = approx. 2.3, or
log-base 2 of y = approx 2.3 - 2, or
log-base 2 of y = approx 0.3
Please, if you are given a graph or graphs, share them along with all instructions for the problem at hand. Thank you.
Answer:
12:15pm
Step-by-step explanation:
1hr=60mins
1hr +15mins= 75 minutes
11:00am + 60mins (1hr)= 12pm
12pm + 15mins= 12:15pm
Hope this helps!
8x²-8x+2-5+x = 8x² - 7x - 3
Thus, g = 7 and h = 3