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Mrac [35]
4 years ago
15

WHAT THE SIMPLEST form of 36/16

Mathematics
1 answer:
AlekseyPX4 years ago
4 0
The simplest form is 2 1/4
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How do you solve this? (#11/#12)
zepelin [54]

\text{If}\ x_1,\ \text{and}\ x_2\ \text{are zeros of a polynomial function, then the function}\\\text{has equation}:\\\\f(x)=a(x-x_1)(x-x_2).\\----------------------------\\\\11.\ \text{We have the zeros}\ 3\ \text{and}\ i:\\\\f(x)=(x-3)(x-i)=(x)(x)+(x)(-i)+(-3)(x)+(-3)(-i)\\\\=x^2-xi-3x+3i=\boxed{x^2-(3+i)x+3i}\\\\12.\ \text{We have the zeros}\ -2\ \text{and}\ 2i:\\\\f(x)=(x-(-2))(x-2i)=(x+2)(x-2i)\\\\=x^2-(2i)^2=x^2-2^2i^2=x^2-4(-1)=\boxed{x^2+4}\\\\\text{used}\\\\(a-b)(a+b)=a^2-b^2\\\\i=\sqrt{-1}\to i^2=-1

3 0
3 years ago
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
3.5c=24.50
c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
4 years ago
Tell whether the system has one solution infinitely many solutions or no solution.
hodyreva [135]
B. hope this helps :)
5 0
4 years ago
Read 2 more answers
Write each phrase as a variable expression <br> 25 less than a number
Andrew [12]

Answer:

25 < number

Step-by-step explanation:

hope it will help you

4 0
3 years ago
330 billion divided by 6.9 billion = ??
kicyunya [14]

Answer:

4.782608696  x  10^10

Step-by-step explanation:

3 0
3 years ago
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