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Amanda [17]
2 years ago
7

A 5 pound bag of candies contains about 2500 pieces. If the company makes 4.7 million bags per year, about how many pieces of ca

ndies are made per year
Mathematics
2 answers:
tamaranim1 [39]2 years ago
7 0

Answer:  The required number of pieces of candies made per year is 11,750,000,000.

Step-by-step explanation:  Given that a 5 pound bag of candies contains about 2500 pieces and the company makes 4.7 million bags per year.

We are to find the number of pieces of candies that are made per year.

We will be using the UNITARY method to solve the given problem.

Number of pieces of candies in a 5 pound bag = 2500

So, the number of pieces of candies in 4.7 million bags will be

2500\times4.7=11750~\textup{million}=11750\times1000000=11750000000.

Since 4.7 million bags are made per year, so the number of pieces of candies that are made per year is 11,750,000,000.

Thus, the required number of pieces of candies made per year is 11,750,000,000.

Aleks04 [339]2 years ago
4 0
<span>Around 11,750,000,000 candies will be made.  Of course there will be damaged ones and lost ones.  Please mark Brainliest!!!</span>
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Pani-rosa [81]

Answer:

2y-8

Step-by-step explanation:

-y-5+y+2(2y-y)-3

Do the parenthesis first

-y-5+y+2(y)-3

Multiply

-y-5+y+2y-3

Combine like terms

2y-8

3 0
2 years ago
Find either the maximum or the minimum value of the following quadratic equation. Be sure to show all of your work and identify
podryga [215]

Answer:

the minimum is (1,-9)

Step-by-step explanation:

y = 5x^2 - 10x - 4

since the parabola opens upward  5>0, this will have a minimum

it will occur along the axis of symmetry h=-b/2a

y =ax^2 +bx+c

h = -(-10)/2*5

h  = 10/10 =1

the minimum occurs at x =1

the y value for the minimum is calculated by substituting x =1 back into the equation

y = 5 * 1^2 - 10*1 -4

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6 0
3 years ago
Witch of the following statements are true​
Sliva [168]
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4 0
2 years ago
The admission fee at an amusement park is 20$ for children and 35$ adults. On a certain, day 264 people entered the park, and th
shtirl [24]

Answer:

100 Adults and 164 Children

Step-by-step explanation:

To solve this we will need to write two equations to solve for the two unknowns. Firstly, we know that tickets are 20 for children and 35 for adults, and that the total price was 6780. We can write an expression to represent this. 6780 is the total price, this also means it is the price of all the adults + the price of all the children. The total price of the adults tickets is the price of each ticket multiplied by the number of adults, so the total price of adult tickets can be represented by: 35A, 35 being the ticket price per adult, and A being the number of adults. Similarly the total children's price can be expressed as such: 20C, 20 being the price per child, and C being the number of children. Since we know that these two values total to 6780, we can now form an equation:

35A (total adult price) + 20C (total children price) = 6780

35A+20C=6780

Now we need another expression so we can substitute for one of the values. The other piece of information we are given, is that a total of 264 people entered the park. This means that the total number of adults + the total number of children = 264. Since we already have variables for the numbers of adults and children we now have our second equation:

A (number of adults) + C (number of children) = 264

A+C=264

Now we can use this second equation to substitute for one of the values in the first equation. Let's substitute for children:

If we rearrange the second expression we will get:

A+C-A=264-A

C=264-A

So now we substitute this expression into our first formula:

35A+20C=6780

C=264-A

35A+20(264-A)=6780

Now since we only have one unknown, we can simplify, expand and solve!

35A+20*264-20*A=6780

35A+5280-20A=6780

35A-20A+5280-5280=6780-5280

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A total of 100 adults were admitted.

Now we can use the number of adults to find the number of children using our second formula:

C=264-A

C=264-100

C=164

And there we are! A total of 100 adults and 164 children were admitted.

Hope this helped!

4 0
3 years ago
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erma4kov [3.2K]

Answer:  374416

Step-by-step explanation:

Given : A test requires that you answer first Part A and then either Part B or Part C.

Part A consists of 4 true false questions, Part B consists of 6 multiple-choice questions with one correct answer out of five, and Part C consists of 5 multiple-choice questions with one correct answer out of six.

i.e. 2 ways to answer each question in Part A.

For 4 questions, Number of ways to answer Part A = 2^4

5 ways to answer each question in Part B.

For 6 questions, Number of ways to answer Part B = 5^6

6 ways to answer each question in Part C.

For 5 questions, Number of ways to answer Part C = 6^5

Now, the number of ways to  completed answer sheets are possible :_

2^4\times5^6+2^4\times6^5\\\\=2^4(5^6+6^5)\\\\=16(15625+7776)\\\\=16(23401)=374416

Hence, the number of ways to  completed answer sheets are possible = 374416

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