<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
<h3>Answers:</h3>
- (a) The function is increasing on the interval (0, infinity)
- (b) The function is decreasing on the interval (-infinity, 0)
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Explanation:
You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).
The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)
Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)
Answer:
The correct answer is 40 cm.
Answer: 33%
Step-by-step explanation:
Answer:6minutes
Step-by-step explanation:
3 hours =180min
180min divided by 30 windows is 6
