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RoseWind [281]
2 years ago
10

HELP PLSSS THIS IS HARD SOMEONEEE

Mathematics
1 answer:
inna [77]2 years ago
6 0

Answer:

it's not even hard

Step-by-step explanation:

......

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(1 - 5q ) +2 (2.5q +8 )
VikaD [51]
Distribute
remember
a(b+c)=ab+ac
2(2.5q+8)=2(2.5q)+2(8)=5q+16

1-5q+5q+16
1+0+16
17
5 0
3 years ago
Please help me quickly, timed test:(​
Dennis_Churaev [7]

Answer:

1 & 7

Step-by-step explanation:

I guessed. Good Luck!

7 0
2 years ago
Read 2 more answers
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

3 0
3 years ago
Answer this ASAP I really need it
Ede4ka [16]
Given the expression
-2 + 6.45z - 6 + (-3.25z)

First, classify like terms, constant with constant, coefficient-variable with coefficient-variable
-2 + 6.45z - 6 + (-3.25z)
= 6.45z + (-3.25z) - 2 - 6

Second, combining like terms
= 6.45z + (-3.25z) - 2 - 6
= 6.45z - 3.25z - 8
= 3.20z - 8

The simplest form is 3.20 - 8
8 0
3 years ago
BRAINLIEST!!!
vichka [17]
I believe the answer is $17500
3 0
3 years ago
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