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Leya [2.2K]
2 years ago
14

Which ion has a charge of 2-?

Chemistry
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

A

Explanation:

More electrons than protons, thus giving the atom an overall charge of -2

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What is Corona virus And explain breifly in​
stira [4]

Answer:

it is a viral disease . it is infected by one person to other .

7 0
3 years ago
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
The air you breathe is made of 21% oxygen and 78% nitrogen. The oxygen in air is the _____ and the nitrogen is the _____.
Flura [38]
Here are the answers that would best complete the given statement above. The air you breathe is made of 21% oxygen and 78% nitrogen. The oxygen in air is the SOLUTE and the nitrogen is the SOLVENT. In a given mixture, the reagent having the highest percentage of amount is always the solvent and the one or ones having the lower percentages are the solutes. Hope this answer helps.
6 0
3 years ago
What is the answer to this question
kvasek [131]

Answer:

b. double bonds, triple bonds, carbon atoms,and hydrogen atoms.

Explanation:

<h2>please mark me brainliest</h2>
3 0
3 years ago
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
DochEvi [55]
Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required
6 0
3 years ago
Read 2 more answers
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