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kvasek [131]
2 years ago
7

If 100.0 g of carbon-14 decays after 2 half lifes, how much of the sample would remain?

Chemistry
2 answers:
Vanyuwa [196]2 years ago
7 0

Answer:

25%

Explanation:

hope it helps

Ainat [17]2 years ago
4 0

Answer:

25 percent

Explanation:

have a good day/ night

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What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
4 years ago
How do you know if an atom is stable?
MArishka [77]
Talk to it about it's emotions and if it breaks down crying immediately then it is unstable. 
4 0
4 years ago
A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
Calculate the value of Kp at 227°C for the equilibrium: 3 A(g) ⇌ B(g) + D(g) Kc = 5.15
horrorfan [7]
D is the answer I guess
3 0
3 years ago
A pool owner adds a compound containing chlorine to the pool to disinfect it. However, too much of the compound is added. As a r
MrMuchimi

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

Cl_2+H_2O\rightarrow HOCl

HOCl\rightarrow HCl+O

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

Acid+Base\rightarrow Salt+water

Adding more acid would increase the acidity further.

3 0
3 years ago
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