Review the equation below.
2 answers:
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Hello!
Data:
P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)
Apply the data to the Clapeyron equation (ideal gas equation), see:
Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl
_________________
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I hope this helps. =)
Data:
P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)
Apply the data to the Clapeyron equation (ideal gas equation), see:
Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl
_________________
_________________
I hope this helps. =)
Solution :
We know that :
and
Then, ..................(1)
Where,
= amount of solvent (in kg)
= amount of solute (in kg)
= molar mass of solute (g/mole)
= molality of solution (mole/kg)
Given :
=
,
= 0.250 kg,
= 24.3 g
Then putting this values in the equation is (1),
g/mole
So, the molar mass of the unknown compound is 158.49 g/mole.