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jenyasd209 [6]
3 years ago
11

How many different arrangements of 55 letters can be formed if the first letter must be w or k​ (repeats of letters are​ allowed

)?
Mathematics
1 answer:
defon3 years ago
3 0
If the remaining 4 letters can be anything, you have 2*26^4 = 913,952 possible 5-letter ham radio call signs.
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Let number of chairs in 1 row be 'x'.
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Given:
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It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.

Also Given:
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Combining like terms we get;

Using Subtraction and Addition property we get;

Now Using Division Property we will divide both side by 2.

Hence there are 7 chairs in each row length.
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