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coldgirl [10]
3 years ago
8

The largest country in the world is Russia with a land area of 16,376,870 km2 Wh area of the Russia in m' 11. A) 1.637687 x10 B)

1.637687 x10 C) 1.637687 x10 D) 1637687 x10" E) 1.637687 x10
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

1.637687 x 10¹³ m²

Explanation:

Land area of Russia has been given in the question as

A = land area of Russia = 16,376,870  km²

we know that

1 km = 1000 m

hence

A = land area of Russia = 16,376,870  (1000 m)² = 16,376,870,000,000 m²

A = 16,376,870,000,000 m²

To represent the area in exponent form, we shift the decimal place from right to left until we have one decimal place.

So we get

A = 1.637687 x 10¹³ m²

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The weight of an iron block is 8.0±0.3? and is placed on a wooden base of area, 3.5±0.2? 2. Calculate the pressure exerted by th
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Explanation:

Units...Nothing is accurate without UNITS. 8.0±0.3 lbs,? Newtons? 3.5±0.2 m²? ft²? cm²? km²? furlong²? fathoms²?

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One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
Anettt [7]

The equilibrium condition allows finding the results for the forces of the system are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition

          ∑ F = 0

Where the bold letters indicate vectors, F is the external forces

a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.

b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force

             N = N₁ + N₂ + N₃ + N₄₄

Let's apply the equilibrium condition

                N -  W_m -w_{table} = 0

                N =  W_m +w_{table}

                N = M_m g + w_{table}  

They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N

                N = 65 9.8 + 100

                N = 737 N

c) To calculate the mass of the table we use the relation

                W = m_{table} g

                m_{table} = \frac{w_{table}}{g}

                m_{tabble}= \frac{100}{9.8}  

               m_{table}e = 10.2 kg

In conclusion using the equilibrium condition we can find the results for the forces are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
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